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If the linear momentum of the object is inceaseby by 0.01% the the kinetic energy is increased by |
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Answer» 0.0001 `P = sqrt(2mE_K)rArr E_K = (P^2)/(2m)` If L is increased by 0.1 % `= P + (0.1)/(100) P` `E_K = ( (P+(0.1)/(100) P)^2)/(2m) = (1.002001P^2)/(2m) = 1.002001E_K` Increase in KINETICENERGY ` = (E_K - E_K)/(E_K) XX 100 = [ (1.002001E_K - E_K)/(E_K) ] xx 100 = 0.2%` |
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