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If the lines \(\frac{x - 1}{-3} = \frac{y - 2}{-2k} = \frac{z - 3}{2},\; \frac{x - 1}{k} = \frac{y - 2}{1} = \frac{z - 3}{5}\) are ⊥r, find k |
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Answer» Directions of tines are (-3, -2K, 2) and (K, 1,5) since lines are ⊥r a1b1 + a2b2 + a3b3 = 0 -3 x K – 2K x 1 + 2 x 5 = 0 -3K – 2K + 10 = 0, -5K = -10, K = 2 |
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