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If the lines L_1 and L_2in space are defined by L_1 = {x=sqrt lambda y+ (lambda-1) z= (sqrtlamda -1) y+sqrtlambda ) and L_2 ={ x=sqrtmu y + (1-sqrtmu ), z =(1-sqrtmu )y +sqrtmu )thenL_ 1is perpendicular to L_2 for all non- negative realslambda and musuch that |
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Answer» ` sqrtlambda +SQRT mu =1` |
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