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If the lines (x-1)/-3 = (y-2)/(2k) = (z-3)/2 and (x-1)/(3k) = (y-1)/1 = (z-6)/-5 are perpendicular, then find the value of k. |
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Answer» SINCE the lines are perpendicular, `-3xx3k+2kxx1+2xx-5=0` `rArr` -9k+2k-10=0 `rArr` 7k=-10 `rArr = (-10)/7` |
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