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If the magnitude of two vectors are 3 and 4 and their scalar product is 6, find angle between them and also find \(|\vec A \times \vec B|\) |
Answer» \(\vec A.\vec B\) = AB cos θ \(|\vec A \times \vec B|\) = AB sin θ or 6 = (3 x 4) cos θ = 3 x 4 x 60° or θ = 60° 3 x 4 x \(\frac{\sqrt3}{2}\) = 6\(\sqrt3\) |
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