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If the magnitude of two vectors are ` 3 ` and `6` and ther scalar product is `9`, find the angle between the two vectors. |
Answer» Here, ` A = 3 , B= 6 , vec A. vec B=9` ` cos theta (vec A.vec B)/(AB) = 9/(3 xx 6) = 1/2 = cos 60^2 ` or theta = 60^@`. |
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