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If the magnitudes of two vectors are `2 and 3` and the magnitude of their scalar product is `3 sqrt 2`, then find the angle between the vectors. |
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Answer» Here, `A =2, B=3, vec A. vec B =3 sqrt2, As vec A. vec B=AB cos theta` So `cos theta =(vec A. vec B)/(AB) =(3sqrt2)/(2xx3) =1/9sqrt2) =cos^(0) , theta =45^(@)`. |
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