If the mass defect of ""_(4)^(9)X is 0.099 a.m.u. , then binding energy per nucelon is (1 a.m.u, 931.5 MeV)

If the mass defect of ""_(4)^(9)X is 0.099 a.m.u. , then binding energ

1.	If the mass defect of ""_(4)^(9)X is 0.099 a.m.u. , then binding energy per nucelon is (1 a.m.u, 931.5 MeV)
Answer» 10.25 MeV 931.5 MeV 83.0 MeV 8.38 MeV Solution :`Deltam=0.099` a.m.u. `E=0.099 XX 931.5` MeV E(per nucleon)`=(0.099xx931.5)/(9)` MeV (No. of NUCLEONS in `""_(4)^(9)X=9`) `=(99xx931.5)/(9xx1000)=10.2465` MeV