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If the mass of each molecule of a gas is halved and speed is doubled , find the ratio of initial and final pressure. |
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Answer» Solution :LET initial and FINAL pressures be `P_1 and P_2` Here, `M_1 = M, C_1 = C, V_1 = V,` `M_2 = M//@, C_2=2C,V_2=V,` As `P_1 = 1/3 M_1/V_1C_1^2` `P_2 =1/3M_2/V_2C_2^2` Ratio of PRESSURE : `:.P_1/P_2=M_1/M_2xxV_2/V_1xxC_1^2/C_2^2` `=M/(M//2)xxV/Vxx(C/(2C))^2=1/2` |
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