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If the mean free path of a gas molecule under certain conditions is 5000Å and the molecular speed is 500 mIs, find(i) the time interval between successive collisions (ii) the collision frequency (number of collisions per unit time) of a gas molecule. |
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Answer» Data : λ = 5000 Å = 5000 × 10-10 m = 5 × 10-7 m, v = 500 m/s (i) speed (v) = \(\frac{distance(\lambda)}{time(T)}\) ∴ The time interval between successive collisions of a gas molecule, T = \(\frac{\lambda}v\) = \(\frac{5\times10^{-7}m}{500\,m/s}\) = 10-9 s (ii) The collision frequency (number of collisions per unit time) of a gas molecule, f = \(\frac1T\) = \(\frac1{10^{-9}\,s}\) = 109 collisions per second |
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