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If the median of 33m 28, 20, 25, 34, x is 29, find the maximum possible value of x. |
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Answer» There are 6 observations i.e. even no. of observations So, median will be: \(\frac{(3rd\,observation\,+\,4^{th}\,observation)}{2}\) Arranging in increasing order: 20, 25, 28, x, 33, 34 If we put any other number at 4th position the n, we will not get the median = 29 So, \(\frac{28+x}{2}=29\) 28 + x = 58 x = 58 – 28 = 30 |
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