1.

If the molecule of HCl were totally polar, the expected value of dipole moment is 6-12 D (debye) but the experimental value of dipole moment was 1.03 D. Calculate the percentage ionic character.A. 17B. 83C. 50D. Zero

Answer» Correct Answer - A
Percent ionic character
`=("Obs. dipole moment")/("Cal. dipole moment")xx100`
`=(1.03D)/(6.12D)xx100=17%`


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