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If the moleucar wt of Na_(2)S_(2)O_(3) and I_(2) are M_(1) and M_(2) respectivly then what will be the equivalent wt of Na_(2)S_(2)O_(3) and I_(2) in the following reaction S_(2)O_(3)^(2-)+I_(2)rarrS_(4)O_(6)^(2-)+2I^(-) |
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Answer» `M_(1)M_(2)` Total INCREASES is O.N of S for two molecules of `Na_(2)S_(2)O_(3)=4xx2.5-2[2(+2)=2` `therefore` totoal INCREAE in O.N of S for two molecules of `Na_(2)S_(2)O_(3)` =1 `therefore` Eq mass =`M_(1)//1=M_(1)` Now `I_(2)rarr2I` total decrease is O.N PER molecule of `I_(2)=0-2(-1)=2` `therefore` Eq mass of `I_(2)=M_(2)//2` |
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