1.

If the moleucar wt of Na_(2)S_(2)O_(3) and I_(2) are M_(1) and M_(2) respectivly then what will be the equivalent wt of Na_(2)S_(2)O_(3) and I_(2) in the following reaction S_(2)O_(3)^(2-)+I_(2)rarrS_(4)O_(6)^(2-)+2I^(-)

Answer»

`M_(1)M_(2)`
`M_(1)M_(2)//2`
`2M_(1),M_(2)`
`Mlt_(1),2 M_(2)`

Solution :`2Na_(2)S_(2)O_(3)=Na_(2)S_(4)O_(6)`
Total INCREASES is O.N of S for two molecules of `Na_(2)S_(2)O_(3)=4xx2.5-2[2(+2)=2`
`therefore` totoal INCREAE in O.N of S for two molecules of `Na_(2)S_(2)O_(3)` =1
`therefore` Eq mass =`M_(1)//1=M_(1)`
Now `I_(2)rarr2I`
total decrease is O.N PER molecule of `I_(2)=0-2(-1)=2`
`therefore` Eq mass of `I_(2)=M_(2)//2`


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