If the momentum of a body is doubled, its KE. increases by (A) 50% (

1.	If the momentum of a body is doubled, its KE. increases by (A) 50% (B) 300% (C) 100% (L) 400%
Answer» Correct option is: (B) 300% Kinetic energy , K = \(\frac{P^2}{2m}\) When momentum p is doubled , the kinetic energy becomes \(K^1 = \frac{(2p)}{2m}\) \(K^1 = 4 (\frac{p^2}{2m})\) \(K^1 = 4K\) increases in kinetic energy = \(\frac{K^1 - K}{K}\) \(= \frac{4K - K}{K} \times 100\) \(\left(\frac{3K}{K}\right) \times 100\) 300% Correct option is: (B) 300%

If the momentum of a body is doubled, its KE. increases by (A) 50% (B) 300% (C) 100% (L) 400%

Answer»

Correct option is: (B) 300%

Kinetic energy , K = \(\frac{P^2}{2m}\)

When momentum p is doubled , the kinetic energy becomes

\(K^1 = \frac{(2p)}{2m}\)

\(K^1 = 4 (\frac{p^2}{2m})\)

\(K^1 = 4K\)

increases in kinetic energy = \(\frac{K^1 - K}{K}\)

\(= \frac{4K - K}{K} \times 100\)

\(\left(\frac{3K}{K}\right) \times 100\)

300%

Correct option is: (B) 300%