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if the momentum of the body is doubled by what percentage does its k.e changes

Answer» Kinetic Energy(E) = 1/2mv^2 ——(1)Momentum(P) = m*v ————(2)From equation 11/2 * m * v *v1/2 * p*vSo, E = 1/2pv.This is the relation that is been induced from these two equations. So kinetic energy become half.\xa0


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