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If the normal at a point P to the hyperbola meets the transverse axis at G, and the value of SG/SP is 6, then the eccentricity of the hyperbola is (where S is focus of the hyperbola) |
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Answer» 2 `a cos theta x +b COT theta y =a^(20+b^(2)` `:. G((a^(2)+b^(2))/(a cos theta),0)` `S (ae,0)` `SP = e (a sec theta) -a` Also `SG =(a^(2)+b^(2))/(a cos theta) -ae =(a^(2)e^(2))/(a cos theta) - ae = e[e(a sec theta)-a]` `rArr SG//SP = e= 6` |
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