1.

If the normal to the curve y(x)=∫x0(2t2−15t+10)dt at a point (a,b) is parallel to the line x+3y=−5,a>1 then the value of |a+6b| is equal to

Answer» If the normal to the curve y(x)=x0(2t215t+10)dt at a point (a,b) is parallel to the line x+3y=5,a>1 then the value of |a+6b| is equal to


Discussion

No Comment Found