InterviewSolution
Saved Bookmarks
| 1. |
If the normal to the curve y(x)=∫x0(2t2−15t+10)dt at a point (a,b) is parallel to the line x+3y=−5,a>1 then the value of |a+6b| is equal to |
|
Answer» If the normal to the curve y(x)=∫x0(2t2−15t+10)dt at a point (a,b) is parallel to the line x+3y=−5,a>1 then the value of |a+6b| is equal to |
|