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If the number of divisions on the circular scale is 100 and number of full rotations given to screw is 8 and distance moved by the screw is 4 mm, then what will be least count of the screw gauge ? |
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Answer» Correct Answer - 0.005 mm Pitch = `(4)/(8)`mm = 0.5 mm L.C. = `(0.5)/(100)` mm = 0.005 mm |
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