If the number of divisons on the vernier scale ofa standard vernier calliper is N, then N is always equal to (N- 1) main scale divisions. Would the vernier calliper be rendered useless if N is equal to fewer number of main scale divisions, for example N = ( N-3) M.S.D.? Why? How would the least count calculations be modified?

If the number of divisons on the vernier scale ofa standard vernier ca

1.	If the number of divisons on the vernier scale ofa standard vernier calliper is N, then N is always equal to (N- 1) main scale divisions. Would the vernier calliper be rendered useless if N is equal to fewer number of main scale divisions, for example N = ( N-3) M.S.D.? Why? How would the least count calculations be modified?
Answer» (i) What is least count? Should the value of least count be large or small/ Will the accuracy of the venier calipers be increased by decreasing the value of the least count? The least count, L.C.=`(1 M.S.D.)/(N)=1 M.S.D-1` V.S.D. Given the principle pf vernier os N V.S.D.=(N-1) M.S.D. This implies that, 1 V.S.D. =`((N-1)/(N))` M.S.D. On substituting(2) in(1) , find the value of L.C. Consider, if N V.S.D. = (N-3) M.S.D. `rArr 1 V. S.D. =`((N-1)/(N))` M.S.D Substituting (3) in (1), find the value of L.C. In which case is the L.C. is teh least?

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