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If the number of nuclei of a radioactive substance becomes 1/e times the initial number in 10 days, what is the decay constant of the substance ? |
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Answer» N(t) = N0e-λt ∴ In this case, \(\cfrac{N(t)}{N_0}\) = \(\cfrac1e\) = e-λt \(\cfrac1{e^{λt}}\) ∴ λt = 1 ∴ The decay constant, λ = \(\cfrac1t\) = \(\cfrac1{10}\) day-1 = 0.1 day-1 |
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