If the numerator of a fraction is increased by 0% and the denominator

1.	If the numerator of a fraction is increased by 0% and the denominator is increased by 40%, then the resultant fraction is \(\frac{{16}}{{63}}\). The original fraction is:1. \(\frac{{4}}{{9}}\)2. \(\frac{{16}}{{45}}\)3. \(\frac{{5}}{{9}}\)4. \(\frac{{2}}{{11}}\)
Answer» Correct Answer - Option 2 : \(\frac{{16}}{{45}}\) Given: Numerator is increased by 0% Denominator is increased by 40% Calculation: Let numerator be x and denominator be y According to the question, 100x/140y = 16/63 ⇒ 5x/7y = 16/63 ⇒ 45x = 16y ∴ \(\frac{{\rm{x}}}{{\rm{y}}} = \frac{{16}}{{45}}\)

If the numerator of a fraction is increased by 0% and the denominator is increased by 40%, then the resultant fraction is \(\frac{{16}}{{63}}\). The original fraction is:1. \(\frac{{4}}{{9}}\)2. \(\frac{{16}}{{45}}\)3. \(\frac{{5}}{{9}}\)4. \(\frac{{2}}{{11}}\)

Answer» Correct Answer - Option 2 : \(\frac{{16}}{{45}}\)

Given:

Numerator is increased by 0%

Denominator is increased by 40%

Calculation:

Let numerator be x and denominator be y

According to the question,

100x/140y = 16/63

⇒ 5x/7y = 16/63

⇒ 45x = 16y

∴ \(\frac{{\rm{x}}}{{\rm{y}}} = \frac{{16}}{{45}}\)

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If the numerator of a fraction is increased by 0% and the denominator is increased by 40%, then the resultant fraction is \(\frac{{16}}{{63}}\). The original fraction is:1. \(\frac{{4}}{{9}}\)2. \(\frac{{16}}{{45}}\)3. \(\frac{{5}}{{9}}\)4. \(\frac{{2}}{{11}}\)

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