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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
?% of 800 = 293 – 22% of 7501). 142). 183). 124). 16 |
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Answer» Given EXPRESSION is, ?% of 800 = 293 – 22% of 750 ⇒ ?% of 800 = 293 – (22/100) × 750 ⇒ ?% of 800 = 293 – 165 ⇒ (?/100) × 800 = 128 ⇒ ? = (128 × 100)/800 ⇒ ? = 16 |
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| 2. |
What is 18% of 45% of 3/8th of8160?1). 2189.282). 76503). 247.864). 436.37 |
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Answer» ALWAYS START from the innermost calculation. LET 3/8th of8160 be 'X' ∴ X = (3/8) × 8160 = 3060 We need to find 45%of'X'. Let the ANSWER to this be 'Y' ∴Y = (45/100) × 3060 = 1377 We need to find 18%of 'Y'. Let the answer to this be 'Z' ∴ Y = (18/100) × 1377 = 247.86 ∴ The answer is 247.86 |
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| 4. |
1). 40 m2). 45 m3). 48 m4). 50 m |
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Answer» TOTAL height of the tree is = 200 m In one jump monkey can climb = 20% of the total height of the tree = 20% of 200 m = 40 m But the monkey will slip down 60% of the height he had jumped = 60% of 40 = 24 m Effective height climbed by monkey in one jump = 40 – 24 = 16 m ∴ Total height climbed by monkey in 3 JUMPS will be = 16 × 3 = 48 m |
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| 5. |
A shopkeeper distributes salaries to his employees P and Q. Total money he distributes to both of them is Rs. 9850, as he adds Rs. 500 to P's salary and Rs. 350 to Q's salary as a bonus, then the ratio of the salary of P to the salary of Q is 90 : 107. Then, what is difference between the original salaries of Q and P?1). Rs. 20002). Rs. 9003). Rs. 10004). Rs. 1200 |
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Answer» <P>Given, Bonus amount of Q = 350 Let the original Salary of P and Q be Rs. P and Rs. Q respectively. Total money he distribute to both after bonus = 9850 ⇒ P + 500 + Q + 350 = 9850 ⇒ P + Q = 9000 Given, The RATIO between salary of P and salary of Q is 90 : 107 after bonus. ⇒ (P + 500)/(Q + 350) = 90/107 ⇒ 107P + 53500 = 90Q + 31500 ⇒ 90Q - 107P = 22000 Solving equation, ⇒ 90Q + 90P = 810000 ⇒ 90Q - 107P = 788000 Subtracting above equation, ⇒ 197P = 788000 ⇒ P = 4000 Then, ⇒ P + Q = 9000 ⇒ Q = 5000 Difference in original salaries of P and Q = 5000 - 1000 = 4000 ∴ Difference in original salaries of P and Q is Rs. 1000. |
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| 6. |
A shopkeeper had some jeans, out of which he sells 12 % jeans and still has 44 jeans remaining. If he had 25% of total clothes are jeans than what is the number of clothes other than jeans?1).2). 953). 604). 75 |
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Answer» Let the total number of clothes = x No of jeans $(= \;x \times \frac{{25}}{{100}} = \frac{1}{4}x)$ After selling 12% jeans, remaining jeans $(= \;\frac{1}{4}x - \frac{1}{4}x \times \frac{{12}}{{100}} = \frac{x}{4} - \frac{{3x}}{{100}} = \frac{{25X\; - \;3x}}{{100}} = \frac{{22x}}{{100}})$ Remaining jeans $(= \frac{{22x}}{{100}} = 44)$ ⇒ 22x = 44 × 100 $(\Rightarrow {\RM{\;}}\frac{{44 \times 100}}{{22}} = 200)$ Number of Jeans $(= \;200 \times \frac{{25}}{{100}} = 50)$ Number of clothes other than jeans = 200 – 50 = 150 |
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| 7. |
If 30% of a number exceeds 20% of the number by 18 then, Find the number.1). 1202). 2003). 1804). 150 |
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Answer» ⇒ 30% of X = 30 X/100 ⇒ 20% of X = 20 X/100 Given that, ⇒ (30 X/100) – (20 X/100) = 18 ⇒ X = 180 |
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| 8. |
Annual income of Sameer is 8 lakh Rs. He spent 15% on Rent, 20% on Food and \(\frac{7}{{13}}\) of remaining on Cloth and travel together. Find the difference between total saving and amount spent on travel annually, if ratio between amount spent on Cloth to travel is 9 : 5.1). Rs. 1250002). Rs. 1650003). Rs. 1400004). Rs. 175000 |
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Answer» ANNUAL income = Rs. 800000 ∴ Expenditure on rent = Rs. 800000 × 15/100 = Rs. 120000 ∴ Expenditure on FOOD = Rs. 800000 × 20/100 = Rs. 160000 ∴ Remaining = Rs. [800000 - (120000 + 160000)] = Rs. 520000 ∴ Expenditure on CLOTH and travel = Rs. 520000 × 7/13 = Rs. 280000 Ratio between amount SPEND on Cloth to travel = 9 ? 5 ∴ Expenditure on travel = Rs. 280000 × 5/(9 + 5) = Rs. 100000 ∴ Total savings = Rs. (520000 - 280000) = Rs. 240000 ∴ Required difference = Rs. (240000 - 100000) = Rs. 140000 |
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| 9. |
In a college election between two rivals, a candidate who got 40% of the total votes polled, was defeated by his rival by 160 votes. The total number of votes polled was1). 9002). 8003). 7004). 600 |
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Answer» LET total number of VOTES polled = 100m. Then number of votes the LOSING candidate got = 40% of 100m ⇒ $(400/100) × 100 m = 40m Number of votes the winning candidate got = 100m – 40m = 60m DIFFERENCE = 60m – 40m = 20m We are given that the difference of winning is 160 votes. ⇒ 20m = 160 ⇒ m = 160/20 ⇒ m = 8 ∴ T$otal number of votes polled = 100m ⇒ 100 × 8 = 800 |
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| 10. |
If 1 is added to 30% of a number and the result so obtained is divided by 7, the output is 103. Find the original number.1). 35002). 36003). 32004). 2400 |
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Answer» 1 + 0.3x = 721 0.3x = 720 x = 2400 |
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| 11. |
Seven litre of water was mixed to 11 litres of sugar solution containing 18% of sugar. What is the percentage of sugar in the solution?1). 102). 113). 184). Insufficient data |
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Answer» GIVEN, seven LITRE of WATER was mixed to 11 litres of sugar SOLUTION containing 18% of sugar. Amount of sugar in 11 litre solution = 18% of 11 = 1.98 litres Given, Water added to the solution = 7 litres ∴ Total solution = 7 + 11 = 18 litres ∴ Percentage of sugar in 18 litres = (1.98/18) × 100 = 11% |
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| 12. |
The production of a company A increased by 25% from 1994 to 1995, and its production further increased by 60% from 1995 to 1996. What is the total percent increase in production of the company from 1994 to 1996?1). 85%2). 90%3). 100%4). Cannot be determined |
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Answer» <P>Percent increase in PRODUCTION of the company from 1994 to 1995 = 25%; Percent increase in production of the company from 1995 to 1996 = 60%; ∴ Required NET percent increase from 1994 to 1996 = {25 + 60 +(25 × 60)/100}% ⇒ $(85 + 15)% = 100% ∴ P$roduction of the company is INCREASED from 1994 to 1996 by 100%. |
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| 13. |
1). 16.38%2). 24.03%3). 28.17%4). 25.75% |
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Answer» We know that, total cost = price of raw materials +labor cost Assume that, INITIAL price of raw materials = R Initial labor cost = 25% of the cost of raw material = 0.25 × R ∴total cost =R + 0.25 × R = 1.25 × R Now, the cost of raw material increases by 15%. Thus, new price of raw materials = R + (15% of R) = 1.15 × R New labor cost = 30% of 1.15R = 0.3 × 1.15R = 0.345R ∴New total cost = new price of raw materials + new labor cost ⇒New total cost = 1.15R + 0.345R = 1.495R Total increase in total cost = 0.245 × R Percentage reduction REQUIRED = $(\frac{{0.245{\rm{\;}} \times {\rm{\;R}}}}{{1.495{\rm{\;}} \times {\rm{\;R}}}} \times 100 = 16.38\% )$ |
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| 14. |
There are 4250 employees in an organization. Out of which 4% got retired and 48% got transferred to different places. How many employees remained in the office?1). 21502). 22403). 20404). 2044 |
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Answer» There are 4250 employees in an ORGANIZATION. Out of which 4% got retired and 48% got transferred to different places So, Total (48 + 4) % = 52% employees LEFT the organization So, remaining employees = 100% - 52% = 48% Remaining employees = 48% of 4250 $(= {\rm{\;}}\frac{{48}}{{100}}\; \times 4250)$ = 2040 |
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| 15. |
Mr. Prakash invests 24% of her monthly salary, i.e. Rs. 12,024 in Insurance Policies. Later he invests 15% of his monthly salary on Family Med claim Policies; also he invests another 17% of his salary on Mutual Funds. What is the total annual amount invested by Mr. Prakash?1). Rs. 2,35,0502). Rs. 3,50,1003). Rs. 3,42,5504). Rs. 3,36,672 |
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Answer» Let the total monthly salary of Mr. PRAKASH = Rs. x Given: 24% of x = Rs. 12,024 Thus, (24/100) × x = 12024 ∴ x = Rs. 50,100 Total monthly salary of Mr. Prakash = Rs. 50,100 He also invested 15% on family med claim and 17% on MUTUAL Funds. Thus, total INVESTMENTS = (24 + 15 + 17) % of 50100 = 56 % of 50100 = (56/100) × 50100 = Rs.28056 Thus, total ANNUAL amount invested by Mr. Prakash = 12 × 28,056 = Rs. 3,36,672. |
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| 16. |
1). 102). 213). 94). 27 |
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Answer» FOLLOW BODMAS RULE to solve this QUESTION, as per the order given below, Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, Step-2: Any MATHEMATICAL 'Of' or 'Exponent' must be solved next, Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated. Given expression is, ⇒ 7.5% of 600 + 11.6 = 72 + (0.4 × ?) ⇒ (7.5/100) × 600 + 11.6 = 49 + (0.4 × ?) ⇒ 45 + 11.6 = 49 + (0.4 × ?) ⇒ 56.6 – 49 = (0.4 × ?) ⇒ 7.6 = 0.4 × ? ⇒ ? = 19 |
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| 17. |
Aman's expense is 30% more than Vimal's expense and Vimal's expense is 10% less than Raman's expense. If the sum of their expenses is Rs. 6447, then what would be the Aman's expense?1). Rs. 2200 2). Rs. 24573). Rs. 18904). Rs. 2100 |
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Answer» LET expenses of AMAN, VIMAL and Raman be Rs. m , Rs. p and Rs. N respectively. Given, ⇒ m = p + p × 30/100 ⇒ m = 13p/10 ⇒ p = 10m/13 Given, ⇒ p = n – n × 10/100 ⇒ p = 9n/10 As, ⇒ 10m/13 = 9n/10 ⇒ n = 100M/117 Given, ⇒ m + n + p = 6447 ⇒ m + 10m/13 + 100m/117 = 6447 ⇒ 117m + 90m + 100m = 6447 × 117 ⇒ 307m = 6447 × 117 ⇒ m = 2457 ∴ Aman expenses is Rs. 2457 |
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| 18. |
Total salary of A, B and C is Rs. 86000. Salary of A is 40% less than salary of B and salary of C is Rs. 5000 less than salary of B. Salary of A is what percent of salary of C?1). 77.77%2). 70%3). 19.99%4). 33% |
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Answer» Let salary of A, B and C be RS. A, Rs. B and Rs. C respectively. Given, ⇒ A + B + C = 86000 Given, Salary of A is 40% less than salary of B. ⇒ A = B - B × (40/100) ⇒ A = 3B/5 Salary of C is Rs. 5000 less than salary of B. ⇒ C = B - 5000 Solving equation, ⇒ 3B/5 + B + B - 5000 = 86000 ⇒ 13B - 25000 = 86000 ⇒ 13B = 455000 ⇒ B = 35000 Salary of A = 35000 × 3/5 = 21000 Salary of C = 35000 - 5000 = 30000 Required percentage = (21000/30000) × 100 = 70% ∴ Salary of A is 70% of salary of C. |
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| 19. |
45% of one-fourth of 50% of price of a mobile is the price of a pen drive. If price of the pen drive is 360. The price of the mobile in Rs. is1). 64002). 57603). 48004). 7200 |
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Answer» Let, The price of the mobile is Rs. X 45% of one-fourth of 50% of x is $(= \frac{{45}}{{100}} \times \frac{1}{4} \times \frac{{50}}{{100}} \times x)$ = 9x/160 According to the question, 9x/160 = 360 ⇒ x = 40 × 160 ⇒ x = 6400 |
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| 20. |
1). 562). 683). 724). 84 |
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Answer» Marks secured = 86.4% of 500 = 86.4/100 × 500 = 432 Marks secured in Mathematics = 22.22% of 432 ≅ 96 Remaining marks = 432 - 96 = 336 Marks secured in Science = Marks secured in English = 25% of 336 = 0.25 × 336 = 84 Remaining marks = 336 - (84 + 84) = 168 ? Equal marks are secured in Hindi, COMPUTERS and ARTS, ∴ Marks secured in Hindi = 168/3 = 56 |
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| 21. |
1). 100%2). 120%3). 160%4). 200% |
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Answer» Let the NUMBER of visitors initially be x. Thus, the total SALE = Rs. 100x Now the ENTRY fee is reduced to 60%. Thus, new entry fee = Rs. 60 The sales are increased by 20%. Thus, new sales = 100x + 20% of 100x = 120x New number of visitors = 120x/60 = 2x % INCREASE in the number of visitors = [(2x - x)/x] × 100 = 100% Hence, there is 100% increase in the visitors. |
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| 22. |
1). Rs. 75002). Rs. 60003). Rs. 66004). Rs. 7200 |
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Answer» Let X be any integer such that 7x and 4x be the earnings of A and B respectively. According to the QUESTION, new earnings of A = (100 - 20)% of 7x And new earnings of B = (100 + 25)% of 4x The ratio of the new earnings = 5 : 3 So, (80% of 7x)/ (125% of 4x) = 5/3 Since the information is not enough to CALCULATE the expenditure of either A or B. Hence, the expenditure cannot be determined. |
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| 23. |
1). 9.375%2). 9.5%3). 10%4). 10.5% |
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Answer» ⇒ ACTUAL price of the PRODUCT before discount = Rs. (29 + 3) = Rs. 32 ⇒ Price after discount = Rs. 29 ⇒ SAVINGS = Actual Price - Purchase Price ⇒ Percentage Savings = [(Actual Price - Purchase Price)/Actual Price] × 100% ⇒ [(32 – 29)/32] × 100% ⇒ (3/32) × 100% ⇒ 75/8% ⇒ 9.375% ∴ % savings = 9.375% |
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| 24. |
Salary of A is Rs. 15000 and his savings percentage is 12% and the rest is the expenditure. Due to slack in the company, the salary of A is decreased by 2% but his expenditure increased by 2%. By how much percent his savings are down due to slack?1). 13.67%2). 10%3). 45.67%4). 31.33% |
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Answer» Given, Savings percentage = 12% Expenditure percentage = 88% Expenditure amount he SPEND = 15000 × 88/100 = 13200 His savings = 15000 - 13200 = 1800 Due to slack, Reduction in salary by 2%. New salary after reduction = 15000 - 15000 × 2/100 = 14700 His expenditure INCREASED by 2%. New expenditure = 13200 + 13200 × 2/100 = 13464 His new savings due to slack = 14700 - 13464 = 1236 Percentage change in savings = {(1800 - 1236)/1800} × 100 = 31.33% |
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| 25. |
1). 63002). 56003). 48004). 4900 |
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Answer» Let the number be ‘x’. $(x \times \FRAC{{36}}{{100}} \times \frac{4}{7} \times \frac{{25}}{{100}} = 288 \RIGHTARROW x = \frac{{288\; \times \;100\; \times \;7\; \times \;100}}{{25\; \times \;4\; \times \;36}} = 5600)$ ∴ x = 5600 |
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| 26. |
1). 200/72). 300/73). 504). 500/7 |
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Answer» <P>P + Q will be positive. SINCE P is greater than Q, (P - Q) will be TAKEN into EQUATION as it will be positive. Here, P + Q = (P - Q) × (1 + 30/100) ⇒ 0.3P = 2.3Q ⇒ P = (2.3/0.3)Q ⇒ P = (23/3)Q = Q × (1 + 20/3) = Q × (1 + (2000/3)/100) ∴ P is greater than Q by (2000/3)% |
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| 27. |
1). 405.12). 450.63). 835.64). 658.5 |
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Answer» Given, 40% of m = N ⇒ (40/100)m = n ⇒ 2m/5 = n ⇒ 2m = 5n 60% of n = 180 ⇒ (60/100) × n = 180 ⇒ 3N/5 = 180 ⇒ 3n = 900 n = 300 2m = 5 × 300 m = 1500/2 = 750 (m - n) = (750 - 300) = 450 85% of (m - n) = (85/100) × (450) = 382.5 |
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| 28. |
1). 2.42). 3.23). 2.84). 4 |
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Answer» We know that, Let old price and sales be P and Q, respectively Old revenue = PQ ∴ NEW price = P × (1 + 10/100) = 1.1P ∴ New sales = Q × (1 - 12/100) = 0.88Q New revenue = (1.1P)(0.88Q) = 0.968PQ ∴ PERCENTAGE by which revenue has decreased = [(PQ - 0.968PQ)/PQ] × 100 = 3.2% |
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| 29. |
A fruit seller bought some pineapples of which 12% of then were rotten. He sold 60% of the balance and was left with 176 pineapples. How many pineapples did he have originally?1). 2002). 1503). 6004). 500 |
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Answer» Now take initial number of pineapples = x. Then ⇒ x × (100 − 12)% × (100 − 60)% = 176 ⇒ x = 176/{(88)% × (40)%} ⇒ (176 × 100 × 100) / (88 × 40) = 500 pineapples was there originally. |
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| 30. |
Every day, the flowers in a garden increase by 50%. At the end of every day, 40 flowers are picked from the garden. Due to this, the number of flowers in the garden remains constant every morning. How many flowers can be found in the garden on any morning?1). 602). 723). 804). 90 |
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Answer» LET the NUMBER of flowers in garden on any morning be N. Every day, the flowers in a garden INCREASE by 50%. At the end of every day, 40 flowers are picked from the garden. Due to this, the number of flowers in the garden remains CONSTANT every morning. ⇒ N(1 + 50/100) – 40 = N ⇒ 0.5N = 40 ⇒ N = 80 ∴ The number of flowers in garden on any morning is 80. |
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| 31. |
An x litres solution contains x% acid. If y litres of water is added to the solution to reduce the acid percentage to (x – 10)%, determine the value of y.1). x2/1002). 10x/(x – 10)3). 10x/(x + 10)4). 10x2/(x – 10) |
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Answer» X litres of SOLUTION of x% acid ⇒ x/100 × x = x2/100 acid in solution(1) New solution = x + y litres % of acid = [(x2/100)/(x + y)] × 100 = x – 10 x2/(x + y) = x – 10 x2 = x2 – 10x + XY – 10y y = 10x/(x – 10) |
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| 32. |
Quantity B: 751). Quantity A > Quantity B2). Quantity A ≥ Quantity B3). Quantity B > Quantity A4). Quantity B ≥ Quantity A |
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Answer» QUANTITY A:$ Maximum marks for all the three SUBJECTS = 100 + 100 + 120 = 320 Marks scored by Cavani in all the three subjects = 75% of 320 = 240 Marks scored by Cavani in ENGLISH = 240 - 80 - 70 = 90 Percentage scored in English = 90 x 100/120 = 75% ∴ Percentage scored in English = 75% Quantity B: 75 Quantity A = Quantity B
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| 33. |
1). 22). 1.53). 2.254). 1.25 |
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Answer» ⇒ 12.5% of 360 + ? × 4 = 34% of 150 $(\Rightarrow \FRAC{{12.5}}{{100}} \times 360 + ? \times 4 = \frac{{34}}{{100}} \times 150)$ ⇒ 45 + ? × 4 = 51 ⇒ ? × 4 = 51 - 45 ⇒ ? = 6/4 ⇒ ? = 1.5 |
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| 34. |
The net sales of an organization in year 2013 is ‘X’. Net sales decrease by 20% in 2014 and increase by 40% in 2015 as compared to the sales in previous years. If the variation in sales in 2016 is equal to the average variation in 2014 and 2015, then find the sales in 2016 in terms of X.1). 1.06X2). 1.12X3). 1.18X4). X |
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Answer» Net sales in 2014 = 20% less than sales in 2013 = 0.8 × X Variation in 2014 = Net sales in 2014 – Net sales in 2013 = -0.2 × X Net sales in 2015 = 40% more than sales in 2014 = 1.4 × 0.8 × X = 1.12 × X Variation in 2015 = Net sales in 2015 – Net sales in 2014 = 1.12X – 0.8X = 0.32X Variation in 2016 = (Variation in 2014 + Variation in 2015)/2 = (-0.2X + 0.32X)/2 = 0.12X/2 = 0.06X Net sales in 2016 = Net sales in 2015 + Variation in 2016 = 1.12X + 0.06X = 1.18X |
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