1.

An x litres solution contains x% acid. If y litres of water is added to the solution to reduce the acid percentage to (x – 10)%, determine the value of y.1). x2/1002). 10x/(x – 10)3). 10x/(x + 10)4). 10x2/(x – 10)

Answer»

X litres of SOLUTION of x% acid

⇒ x/100 × x = x2/100 acid in solution(1)

New solution = x + y litres

% of acid = [(x2/100)/(x + y)] × 100 = x – 10

x2/(x + y) = x – 10

x2 = x2 – 10x + XY – 10y

y = 10x/(x – 10)


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