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                                    If the ordered triplets of real numbers(x,y,z) satisfy \sqrt{x-y+z} = \sqrt x-\sqrt y+\sqrt z , x+y+z=8 and x-y+z=4 then find xyz. | 
                            
| Answer» If the ordered triplets of real numbers(x,y,z) satisfy \sqrt{x-y+z} = \sqrt x-\sqrt y+\sqrt z , x+y+z=8 and x-y+z=4 then find xyz. | |