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If the pair of lines a x^(2)+2 h x y+b y^(2)=0 is rotated about the origin through 90^(0), then their equation in the new position is given by |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/ax-889785" style="font-weight:bold;" target="_blank" title="Click to know more about AX">AX</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)-2hxy-by^(2)=<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>`<br/>`ax^(2)-2hxy+by^(2)=0`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/bx-906513" style="font-weight:bold;" target="_blank" title="Click to know more about BX">BX</a>^(2)+2hxy+ay^(2)=0`<br/>`bx^(2)-2hxy+ax^(2)=0`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |