If the papers of 4 students randomly distributed for checking among 7 teachers, then the probability that all the 4 papers are checked by exactly 2 teachers is nm where n,m are natural numbers and HCF(n,m)=1. Then the number of positive divisors of (n+m) is

If the papers of 4 students randomly distributed for checking among 7

1.	If the papers of 4 students randomly distributed for checking among 7 teachers, then the probability that all the 4 papers are checked by exactly 2 teachers is nm where n,m are natural numbers and HCF(n,m)=1. Then the number of positive divisors of (n+m) is
Answer» If the papers of $4$ students randomly distributed for checking among $7$ teachers, then the probability that all the $4$ papers are checked by exactly $2$ teachers is $\frac{n}{m}$ where $n, m$ are natural numbers and $H C F (n, m) = 1$ . Then the number of positive divisors of $(n + m)$ is

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If the papers of 4 students randomly distributed for checking among 7 teachers, then the probability that all the 4 papers are checked by exactly 2 teachers is nm where n,m are natural numbers and HCF(n,m)=1. Then the number of positive divisors of (n+m) is

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