InterviewSolution
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InterviewSolution
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If the pdf of a curve X is `f(x)={{:(k.e^(-thetax)","thetagt0","0lexltoo),(0","ooltxlt0" then k is equal to"):}`A. 1B. `theta/2`C. `theta`D. `2theta` |
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Answer» Correct Answer - C `thereforef(x)` is the pdf `therefore" "oversetoounderset(-oo)intf(x)dx=1rArroversetoounderset0intk.e^(-thetax)dx=1` `rArr" "k[e^(-thetax)/(-theta)]_0^oo=1` `rArr" "=k/theta[1/e^(thetax)]_0^oo=1` `rArr" "-k/theta[1/e^oo-1/e^0]=1` `rArr" "-k/theta[1/oo-1/1]=1` `rArr" "-k/theta[0-1]=1rArrk/theta=1` `therefore" "k=theta` |
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