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If the peak value of an alternating emf is 10 V, what is its mean value over half cycle? |
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Answer» eav = 0.6365 e0 = 0.6365(10) = 6.365 V Note: In general, when e = e0 sin ωt, the correspond ing current is j = i sin (ωt + α), where α is the phase difference between emf e and current j. ¿z may be positive or negative or zero. i0 is the peak value of the current and iav (over half cycle) = \(\cfrac2{\pi}\) i0 = 0.6365 i0]. |
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