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If the percentage decrease in the length of a simple pendulum is 10%, then find the percentage decrease in its time period |
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Answer» Solution :(i) `l_(2) = l_(1) -10% " of " l_(1), (T_(1))/(T_(2)) = SQRT((l_(1))/(l_(2))), (T_(1) - T_(2))/(T_(1)), xx 100` (ii) 5% |
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