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If the point of suspension of a simple pendulum is in a horizontal motion, with constant acceleration, what will be the effect on the time period? |
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Answer» Solution :When the point of suspension moves horizontally with a constant acceleration a, the effective acceleration due to gravity with RESPECT to the point of suspension, `G.=sqrt(g^(2)+a^(2))` `therefore` Time period, `T=2pisqrt(L/((g^(2)+a^(2))^(1//2)))""...(1)` From EQUATION (1), it is understood that the time period DECREASES due to the increase in the value of accleration of the bob. |
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