1.

if the points h k lies on the line 2x 3y = 5 such that |PA-PB| is maximum where A(2,3) and B(1,2) then the value of 3h+2k=

Answer»

∣PA−PB∣<AB

∣PA-PB∣max​=AB

In this case P, A & B are collinear
So 'P' is intersecting point of these two lines 

Equation of AB: y-x=1

                                        2x+3y=5
therefore answer is 4  


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