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If the points with position vectors 10hati+3hatj, 12hati-5hatj and ahati+11hatj are collinear, find the value of a. |
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Answer» SOLUTION :LET the points are A,B and C. As A,B and C are co-llinear. We have `VEC(AB)` = `vec(AC)` `vec(AB)` = `lambdavec(AC)` `IMPLIES (12i-5j)-(10i+3) = `lambda[(ai+11j)-(10i+3j)]` `implies` 2i-8j = `(a-10)lambdai+8lambdaj` Comparing the components we have `8lambda`= -8 `implies lambda` = -1(a-10)(-1) = 2 `implies` -a+10 = 2 `implies` a= 8. |
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