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If the polynomial `ax^(3)+3x^(2)-3` leaves the remainder 6 when divided by x-4, then find the value of a. |
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Answer» Let x-4=0 `implies x=4` Let `p(x)=ax^(3)+3x^(2)-3` Given that p(4)=6 `implies a(4)^(3)+3(4)^(2)-3=6` `implies 64a+48-3=6` `implies 64a=6+3-48=-39` `implies a=(-39)/(64)` |
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