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If the polynomial x19 + x17 + x13 + x11 + x7 + x5 + x3 is divided by (x2 + 1), then the remainder is :(a) 1 (b) x2 + 4 (c) –x (d) x |
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Answer» (c) – \(x\). f(x) = x19 + x17 + x13 + x11 + x7 + x5 + x3 Putting x2 = – 1, we get f(x) = (x2)9.\(x\) + (x2)8.\(x\) + (x2)6.\(x\) + (x2)5.\(x\) + (x2)2.\(x\) + x2.\(x\) = (–1)9\(x\) + (–1)8.\(x\) + (–1)6.x + (–1)5.\(x\) + (–1)2.\(x\) + (–1).\(x\) = – \(x\) + \(x\) + \(x\) – \(x\) + \(x\) – \(x\) = – \(x\). |
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