1.

If the polynomial x19 + x17 + x13 + x11 + x7 + x5 + x3 is divided by (x2 + 1), then the remainder is :(a) 1 (b) x2 + 4 (c) –x (d) x

Answer»

(c)  – \(x\).

f(x) = x19 + x17 + x13 + x11 + x7 + x5 + x3 

Putting x2 = – 1, we get 

f(x) = (x2)9.\(x\) + (x2)8.\(x\) + (x2)6.\(x\) + (x2)5.\(x\) + (x2)2.\(x\) + x2.\(x\) 

= (–1)9\(x\) + (–1)8.\(x\) + (–1)6.x + (–1)5.\(x\) + (–1)2.\(x\) + (–1).\(x\) 

= – \(x\) + \(x\) + \(x\)\(x\) + \(x\)\(x\) = – \(x\).



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