If the position vector of the particle is given by vecr = 3 t^2 hati + 5t hatj + 4hatk.Find the velocity of the particle at t = 3s.

If the position vector of the particle is given by vecr = 3 t^2 hati +

1.	If the position vector of the particle is given by vecr = 3 t^2 hati + 5t hatj + 4hatk.Find the velocity of the particle at t = 3s.
Answer» <html><body><p></p>Solution :The velocity `vecv = (dvecr)/(dt) = (dx)/(dt) hati + (dy)/(dt) hatj + (dz)/(dt) <a href="https://interviewquestions.tuteehub.com/tag/hatk-2693615" style="font-weight:bold;" target="_blank" title="Click to know more about HATK">HATK</a> ` <br/>we obtain `vecv (t) = 6t hati + 5 hatj` <br/> The velocity has only two components `v_x = 6t` , depending on <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> t and ` v_y = 5` which is <a href="https://interviewquestions.tuteehub.com/tag/independent-505826" style="font-weight:bold;" target="_blank" title="Click to know more about INDEPENDENT">INDEPENDENT</a> of time . <br/> The velocity at t = 3s is `vecv (<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) = 18 hati + 5hatj `</body></html>