If the potential energy of the particle is alpha-(beta)/(2)x^(2), then force experienced by the particle is:

If the potential energy of the particle is alpha-(beta)/(2)x^(2), then

1.	If the potential energy of the particle is alpha-(beta)/(2)x^(2), then force experienced by the particle is:
Answer» `F=(beta)/(2)X^(2)` `F=betax` `F=-betax` `F=-(beta)/(2)x^(2)` SOLUTION :`F=(dw)/(dx)` `=(d)/(dx)(alpha-(beta)/(2)x^(2))` `=(-beta(2X))/(2)=-betax`