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If the pressure of a gas contained in a closed vessel is increased by 0.4% when heated by `1^(@)C`, then its initial temperature must be:A. `-23^(@)C`B. `+23^(@)C`C. `250^(@)C`D. `523^(@)C` |
Answer» `LetT_(1)=T Rightarrow T_(2)=(T+1)` `p_(1)=p Rightarrow p_(2)=p+(0.4p)/(100)=(100.4)/(100)p` `(p_(1)V_(1))/(T_(1))=(p_(2)V_(2))/(T_(2)),(pV)/(T)=(100.4p)/(100)xx(V)/((T+1))` `100T+100=100.4T` `T=(100)/(0.4)=250K` `(250-273)^(@)C=-23^(@)C` |
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