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If the pressure of a gas is doubled and the temperature is tripled, by how much will the mean free path of a gas molecule in a vessel change?A. Increase `3` timesB. Decrease `3` timesC. Increase `1.5` timesD. Decrease `1.5` times |
Answer» `lambda_(1)=(T_(1))/(P_(1))`, `lambda_(2)=(T_(2))/(P_(2))` `:. (lambda_(2))/(lambda_(1))=(T_(2)xxP_(1))/(T_(2)xxT_(1))=(3T_(1)xxP_(1))/(2P_(1)xxT_(1))=(3)/(2)` `lambda_(2)=(3)/(2)lambda_(1)` |
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