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If the projection of the line x/2=(y-1)/2=(z-1)/1 on a plane P is x/1=(y-1)/1=(z-1)/-1. Then the distance of plane P from origin is |
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Answer» `SQRT(3)` `therefore` Plane through these lines is PERPENDICULAR to the plane P. Normal to the plane determined by the given lines is. `|{:(hati,HATJ,hatk),(2,2,1),(1,1,-1):}|=-3hati+3hatj` |
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