1.

If the projection of the line x/2=(y-1)/2=(z-1)/1 on a plane P is x/1=(y-1)/1=(z-1)/-1. Then the distance of plane P from origin is

Answer»

`SQRT(3)`
`sqrt(3/2)`
`sqrt(6)`
`2/sqrt(3)`

SOLUTION :Projection of line `x/2=(y-1)/2=(z-1)/1` on a plane P is `x/1=(y-1)/1=(z-1)/-1`.
`therefore` Plane through these lines is PERPENDICULAR to the plane P.
Normal to the plane determined by the given lines is.
`|{:(hati,HATJ,hatk),(2,2,1),(1,1,-1):}|=-3hati+3hatj`


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