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If the projection of the vector a on b is |axxb| and if 3b=hati+hatj+hatk, then the angle between a and b is |
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Answer» `(pi)/(3)` `rArr (a.b)/(|b|)=|axxb|` `rArr (|a||b|costheta)/(|b|)=|a||b|sintheta` `rArr tan theta=(1)/(|b|)` `rArr tan theta= (1)/((1)/(3)sqrt(1^2+1^2+1^2))` `rArr tan theta = sqrt(3)` `rArr theta=(pi)/(3)` . |
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