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If the radius of 3rd orbit of hydrogen atom is 'x' then the radius of 4th orbit of Li^(2+) ion would be: |
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Answer» `(27)/(16)X` `x=(9)/(1)xx0.529`Ã…. . .(i) `r_(4)(Li^(2+))=(16)/(3)xx0.529`Ã… . . . . (ii) Dividing eqns. (ii) by (i) `(r_(4)(Li^(2+)))/(x)=(16)/(27)` `r_(4)(Li^(2+))=(16xx x)/(27)`. |
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