1.

If the radius of 3rd orbit of hydrogen atom is 'x' then the radius of 4th orbit of Li^(2+) ion would be:

Answer»

`(27)/(16)X`
`(16)/(27)x`
`(9)/(16)x`
`(16)/(9)x`

SOLUTION :`R=(N^(2))/(Z)xx0.529`Ã…
`x=(9)/(1)xx0.529`Ã…. . .(i)
`r_(4)(Li^(2+))=(16)/(3)xx0.529`Ã… . . . . (ii)
Dividing eqns. (ii) by (i)
`(r_(4)(Li^(2+)))/(x)=(16)/(27)`
`r_(4)(Li^(2+))=(16xx x)/(27)`.


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