If the radius of an atom of an element is 75 pm and the lattice type is body-centred cubic , what is the edge of the unit cell ?

If the radius of an atom of an element is 75 pm and the lattice type i

1.	If the radius of an atom of an element is 75 pm and the lattice type is body-centred cubic , what is the edge of the unit cell ?
Answer» Solution :For BCC , ` r = SQRT3/ 4 a or a = ( 4R)/SQRT 3 = ( 4XX 75)/ 1.732= 1.732` PM.