If the radius of anion is `0.20 nm`, the maximum radius of cation which can be filleed in respective voids is correctly matched inA. `r_(o+) = 0.0828 nm` for tetrahedral voidB. `r_(o+) = 0.045 nm` for triangular voidC. `r_(o+) = 0.1464 nm` for tetrahedral voidD. None of the above.

If the radius of anion is `0.20 nm`, the maximum radius of cation whic

1.	If the radius of anion is `0.20 nm`, the maximum radius of cation which can be filleed in respective voids is correctly matched inA. `r_(o+) = 0.0828 nm` for tetrahedral voidB. `r_(o+) = 0.045 nm` for triangular voidC. `r_(o+) = 0.1464 nm` for tetrahedral voidD. None of the above.
Answer» Correct Answer - A::B::C `r_(o+) // r_(ɵ) = 0.732, 0414`, and `0.225` maximum for `OV, TV`. and angular triangular defect.

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If the radius of anion is `0.20 nm`, the maximum radius of cation which can be filleed in respective voids is correctly matched inA. `r_(o+) = 0.0828 nm` for tetrahedral voidB. `r_(o+) = 0.045 nm` for triangular voidC. `r_(o+) = 0.1464 nm` for tetrahedral voidD. None of the above.

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