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If the radius of `K^(+)` and `F^(-)` are 133pm and 136pm respectively, the distance between `K^(+)` and `F^(-)` in KF isA. 269pmB. 134.5pmC. 136pmD. 3pm |
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Answer» Correct Answer - 1 `r_(k^(+))r_(F^(-))=269 "pm"` |
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