1.

If the radius of the circle touching the pair of lines 7x^(2) - 18 xy +7y^(2) = 0 and the circle x^(2) +y^(2) - 8x - 8y = 0, and contained in the given circle is equal to k, then k^(2) is equal to

Answer»

10
9
8
7

Solution :
`tan theta = |(2sqrt(h^(2)-AB))/(a+b)| =(4sqrt(2))/(7)`
`:. tan. (theta)/(2) = (1)/(2sqrt(2))`
`:. sin .(theta)/(2) = (1)/(3) = (SQRT(2)(8-alpha))/(sqrt(2)alpha)`
`:. alpha = 6`
Hence, EQUATION of CIRCLE is `(x-6)^(2) +(y-6)^(2) = 8`.


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