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If the radius of the earth becomes half of its present value but its density remains unchanged then find the weight of body on the surface of earth.

Answer» <html><body><p></p>Solution :`implies g =(GM_(e))/R_e^2=G/(R_e^2)(4/3piR_e^3rho)=4/3 piR_erho`<br/>Since the <a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> becomes <a href="https://interviewquestions.tuteehub.com/tag/half-1014510" style="font-weight:bold;" target="_blank" title="Click to know more about HALF">HALF</a>, <br/> `g. = 4/3 piG((R_e)/2)rho =1/2 (4/3 pi GR_erho)` <br/> `:. g. =g/2 ` soweight becomes half <br/> Weight `W <a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> g` <br/> `:. (W.)/W = (g.)/g` <br/> `:. W. = W <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 1/2` <br/> ` :. W. = W/2`</body></html>


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