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If the radius of the earth is suddenly halved keeping its mass constant find its time period of rotation around its own axis

Answer»

SOLUTION :When the radius of the earth gets reduced suddenly keeping its mass constant, the angular momentum of the earth constant.
`Iomega` =constant
`(2)/(5)MR^(2)xx(2PI)/(T)` constant t
since mass .M. is constant `:.R^(2)ALPHAT`
The radius changes FORM R to R/2.
`(R^(2))/(((R^(2))/(4)))=(24"hour")/(T)"":.T=6` hour


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