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If the radius of the earth is suddenly halved keeping its mass constant find its time period of rotation around its own axis |
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Answer» SOLUTION :When the radius of the earth gets reduced suddenly keeping its mass constant, the angular momentum of the earth constant. `Iomega` =constant `(2)/(5)MR^(2)xx(2PI)/(T)` constant t since mass .M. is constant `:.R^(2)ALPHAT` The radius changes FORM R to R/2. `(R^(2))/(((R^(2))/(4)))=(24"hour")/(T)"":.T=6` hour |
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