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If the radius of the first Bohr orbit is x, then de- Broglie wavelength of electron in 3rd orbit is nearly |
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Answer» 3x `:. mv ((a_(0) n^(2))/(Z)) = (nh)/(2pi)` For 3rd orbit, n = 3 and for hydrogen, Z = 1 `a_(0) = x` (Given, BOHR radius of H-atom) Hence, `mv(x xx 3^(2))/(1) = (3h)/(2pi) or mv = (h)/(6pi x)` `LAMDA = (h)/(mv) = (h)/(h//6pi x_ 6pi x` |
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