If the rate of a reaction is given as (-rA) = \(\frac{k_1+C_A^2}{k_2×C_A} \frac{mol}{m^3 min} \), then the units of k1 and k2 respectively are ____(a) \(\frac{mol^2}{m^6} \) and min(b) min and \(\frac{mol^2}{m^6} \)(c) mol and min(d) m^3 and molThis question was addressed to me during an interview.Enquiry is from Conversion and Reactor Sizing topic in portion Ideal Reactors for a Single Reaction, Conversion and Reactor Sizing of Chemical Reaction Engineering

If the rate of a reaction is given as (-rA) = \(\frac{k_1+C_A^2}{k_2×

1.	If the rate of a reaction is given as (-rA) = \(\frac{k_1+C_A^2}{k_2×C_A} \frac{mol}{m^3 min} \), then the units of k1 and k2 respectively are ____(a) \(\frac{mol^2}{m^6} \) and min(b) min and \(\frac{mol^2}{m^6} \)(c) mol and min(d) m^3 and molThis question was addressed to me during an interview.Enquiry is from Conversion and Reactor Sizing topic in portion Ideal Reactors for a Single Reaction, Conversion and Reactor Sizing of Chemical Reaction Engineering
Answer» The correct ANSWER is (a) \(\FRAC{mol^2}{m^6} \) and min To explain: Two QUANTITIES of the same DIMENSIONS can only be added. As the unit of concentration is \(\frac{mol^2}{m^3} \) , k1 has the units \(\frac{mol^2}{m^6} \). Equating the units of all known quantities on both sides, \(\frac{mol}{m^3 min} = \frac{mol^2}{m^6} × \frac{1}{k_2×(\frac{mol}{m^3})}. \) Hence, k2 has the unit of min.

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