If the resistance of an electric iron is 70 Ω and a current of 3.2 A

1.	If the resistance of an electric iron is 70 Ω and a current of 3.2 A flows through the resistance. Find the voltage between two points.
Answer» Given :- Resistance = 70Ω Current = 3.2A To Find :- VOLTAGE Solution :- ACCORDING to Ohm's LAW :- $\bf <klux>V</klux> = IR$ V denotes voltage I denotes current R denotes resistance Substitute the values :- $: \implies \sf V = 3.2 \times 70$ $: \implies \sf V = 32 \times 7$ $: \implies \sf V = 224$ Voltage between two points = 224V